给出伪代码：（可以看出时间复杂度为O(n^3))1for(intlen=1;len<=n;len++){///len为区间长度2for(intl=1;l<=n-len+1;l++){3intr=l+len-1;4for(intk=l;k<r;k++){5m[l][r]=min(...

证明就是反复利用平方差公式：n=1+(n−1)⋅(n+1)−−−−−−−−−−−−−−−−−√f(x)=1+x1+(x+1)1+(x+2)1+...−−−−−√−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−...

说起一元二次不等式的解法真的不记得了，只是大概记得和一元二次方程的两个根有关系。(x+1)(x-3)<0这个不等式的集解如果熟悉解法的同学可能一秒就知道答案了，-1<x<3 对于不熟悉解法的同学怎么办呢？我这里说下我的方法。(x+1)(x-3)这是什么？我们把x+1看作一个数，x-3看作另外...

评:证明时对求导要求较高，利用这个观点，对平时熟悉的调和平均，几何平均，算术平均，平方平均有了更深    刻的认识....

https://www.bbsmax.com/A/nAJvbKywJr/引用类型比较的是引用，需要自己实现IEqualityComparer比较器。IList<string>strList1=newList<string>(){"One","Two","Three","Four","Three"...