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#恒等式
拉马努金恒等式
证明就是反复利用平方差公式:n=1+(n−1)⋅(n+1)−−−−−−−−−−−−−−−−−√f(x)=1+x1+(x+1)1+(x+2)1+...−−−−−√−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√−−−−−...
代码星球
·
2020-04-15
拉马
努金
恒等式
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