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#Poj
poj 1279 Art Gallery
/*poj1279ArtGallery-求多边形核的面积*/#include<stdio.h>#include<math.h>#include<algorithm>usingnamespacestd;constdoubleeps=1e-8;structpoint{doublex,y;...
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·
2020-10-21
poj
1279
Art
Gallery
poj3295
本题虽然简单,但是利用了编译原理里面的自顶向下方法来设计语法树,递归求解。例如:对于逻辑表达式A&B|C,得到以下输出 ABC A&B|C 000 0 001 1 010 0&...
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2020-10-21
poj3295
poj 1611 The Suspects(并查集)
TheSuspectsTimeLimit: 1000MS MemoryLimit: 20000KTotalSubmissions: 18723 Accepted: 9041DescriptionSevereacuterespiratorysyndrome(SA...
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2020-10-21
poj
1611
The
Suspects
查集
poj 1068 Parencodings (模拟)
ParencodingsTimeLimit:1000MS MemoryLimit:10000KTotalSubmissions:17169 Accepted:10296DescriptionLetS=s1s2...s2nbeawell-formedstringofparentheses.Scanbe...
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2020-10-21
poj
1068
Parencodings
模拟
POJ1651:Multiplication Puzzle(区间DP)
DescriptionThemultiplicationpuzzleisplayedwitharowofcards,eachcontainingasinglepositiveinteger.Duringthemoveplayertakesonecardoutoftherowandscoresthenumberofpoi...
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·
2020-10-21
POJ1651
Multiplication
Puzzle
区间
DP
POJ 2498 Martian Mining
MartianMiningTimeLimit:5000MS MemoryLimit:65536KTotalSubmissions:2194 Accepted:1326DescriptionTheNASASpaceCenter,Houston,islessthan200milesfromSanAnto...
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2020-10-21
POJ
2498
Martian
Mining
POJ3056:The Bavarian Beer Party(区间DP)
DescriptionTheprofessorsoftheBayerischeMathematikerVereinhavetheirannualpartyinthelocalBiergarten.Theyaresittingataroundtableeachwithhisownpintofbeer.Asaceremon...
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2020-10-21
POJ3056
The
Bavarian
Beer
Party
poj 1654 Area 多边形面积
/*poj1654Area多边形面积题目意思很简单,但是1000000的point开不了*/#include<stdio.h>#include<math.h>#include<string.h>constintN=1000000+10;constdoubleeps=1e-8;stru...
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2020-10-21
poj
1654
Area
多边形
面积
poj 2255 Tree Recovery
TreeRecoveryTimeLimit: 1000MS MemoryLimit: 65536KTotalSubmissions: 9658 Accepted: 6067 DescriptionLittleValentinelikedp...
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2020-10-21
poj
2255
Tree
Recovery
poj3348 Cows 凸包+多边形面积 水题
/*poj3348Cows凸包+多边形面积水题floor向下取整,返回的是double*/#include<stdio.h>#include<math.h>#include<algorithm>usingnamespacestd;constdoubleeps=1e-8;structp...
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·
2020-10-21
poj3348
Cows
凸包
多边形
面积
poj1066
很好的一道题。题意是,一个正方形围墙内有一些交错的内墙,内墙的端点都在正方形上,在正方形内部有一个点,求从正方形外到这个点的最少要走的门数,门只能是线段的中点。思路很巧妙,因为从一个点到终点不可能“绕过”围墙,只能传过去,所以门是否开在中点是无所谓的,只要求四周线段中点到终点的线段与墙的最少交点...
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2020-10-21
poj1066
POJ2250:Compromise(LCS)
DescriptionInafewmonthstheEuropeanCurrencyUnionwillbecomeareality.However,tojointheclub,theMaastrichtcriteriamustbefulfilled,andthisisnotatrivialtaskforthecount...
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2020-10-21
POJ2250
Compromise
LCS
poj2993 poj2669
扯淡题。2993 #include<iostream>#include<stdio.h>#include<string>#include<stdlib.h>usingnamespacestd;charmap[10][10];intmain(){stringwas...
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2020-10-21
poj2993
poj2669
POJ 1250 Tanning Salon
TanningSalonTimeLimit: 1000MS MemoryLimit: 10000KTotalSubmissions: 6822 Accepted: 3686 DescriptionTanYourHide,Inc.,owns...
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2020-10-21
POJ
1250
Tanning
Salon
HDU1159 && POJ1458:Common Subsequence(LCS)
ProblemDescriptionAsubsequenceofagivensequenceisthegivensequencewithsomeelements(possiblenone)leftout.GivenasequenceX=<x1,x2,...,xm>anothersequenceZ=<z...
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2020-10-21
HDU1159
POJ1458
Common
Subsequence
LCS
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