JumpingHaybales  题意：从左上角到右下角，‘#’不能落脚，每次可以向下或者向右跳小于等于k的距离，问最小需要多少步到达右下角分析：设dp[i][j]表示到达点坐标点(i),(j)所需的最少步数，状态见代码AC_Code:1#include<bits/stdc++.h>2u...

SuperJumping!Jumping!Jumping!TimeLimit:2000/1000MS(Java/Others)   MemoryLimit:65536/32768K(Java/Others)TotalSubmission(s):47017   ...