ORA-23654: Attempting to set the oldest SCN to a greater value (string) than the current one (string) at Apply string
文档解释ORA-23654:AttemptingtosettheoldestSCNtoagreatervalue(string)thanthecurrentone(string)atApplystringCause:ThenewvaluefortheoldestSCNwasnotcomputedcorrectly.Ac...
MySQL Error number: MY-011688; Symbol: ER_GRP_RPL_FLOW_CTRL_MIN_QUOTA_GREATER_THAN_MAX_QUOTA; SQLSTATE: HY000
文档解释Errornumber:MY-011688;Symbol:ER_GRP_RPL_FLOW_CTRL_MIN_QUOTA_GREATER_THAN_MAX_QUOTA;SQLSTATE:HY000Message:group_replication_flow_control_min_quotacannotbelar...
MySQL Error number: MY-011689; Symbol: ER_GRP_RPL_FLOW_CTRL_MIN_RECOVERY_QUOTA_GREATER_THAN_MAX_QUOTA; SQLSTATE: HY000
文档解释Errornumber:MY-011689;Symbol:ER_GRP_RPL_FLOW_CTRL_MIN_RECOVERY_QUOTA_GREATER_THAN_MAX_QUOTA;SQLSTATE:HY000Message:group_replication_flow_control_min_recover...
greatest among three numbers
publicclassSolution{publicstaticvoidmain(String[]args){Scannerip=newScanner(System.in);System.out.print("EnterA:");inta=ip.nextInt();System.out.print("Ent...
leetcode538. Convert BST to Greater Tree
https://www.cnblogs.com/grandyang/p/6591526.html这个题本质上是中序遍历的反向。中序遍历是从小到大，而这个题目是从大到小，然后每个数加上比自己大的所有数的和。因为实际上并没有改变树的结构，只是改变了原来树中节点的值，所以用void做返回值就可以了。每次加sum实际上就是加的...
C++：greater<int>和less<int>
greater和less是xfunctional.h中的两个结构体，代码如下：1template<class_Ty=void>2structless3{//functorforoperator<4typedef_Tyfirst_argument_type;5typedef_Tysecond_argum...
RegexKit: A Regular Expression Toolbox Based On NW.js(Node-Webkit) And Other Greate Open Source Projects.
RegexKit:ARegularExpressionToolboxBasedOnNW.js(Node-Webkit)AndOtherGreateOpenSourceProjects.RegexKitisbasedonaseriesofgreateopensourceprojects.NW.js:NW.jsExpres...