原文:/l_d_56/article/details/84832198
输入一个时间,获取这个时间的下一秒
PS:下面代码使用于 python 2.7
time1 = raw_input("输入一个时间[HH:MM:SS]:") time1List = time1.split(":") time1List = [int(x) for x in time1List] shi = time1List[0] fen = time1List[1] miao = time1List[2] if miao == 59: miao = 0 fen += 1 if fen == 60: fen = 0 shi += 1 if shi == 24: shi = 0 else: miao += 1 print '输出下一秒的时间为:%02d:%02d:%02d' % (shi, fen, miao)
输出:
输入一个时间[HH:MM:SS]:11:03:00 输出下一秒的时间为:11:03:01 Process finished with exit code 0